Form Or Otc V: Fill & Download for Free

On Avito, Russia’s Craigslist, the number of searches "coronavirus" has increased 900 times from the beginning of the year. There are many entrepreneurs meeting the growing demand with their funky and outrageously overpriced merchandise.A St. Petersburg entrepreneur offered this Chinese magical potion to protect from Covid-19 infection for 1.6 million rubles ($1 USD is worth 80 Russian rubles). Allegedly it heats up sensing a threat of infection. Some potions and amulets fetch as much as 10–15 million rubles.This statue of Dr. Dolittle goes for 8,000 rubles ($100). The cost of amulets in the form of figurines and medallions ranges from a thousand to millions of rubles. Some sellers offer to bless their merchandise in the church for an additional fee.This Soviet soap goes for 100 ruble a bar on Avito. It was used as laundry detergent in the country that sincerely tried to defeat capitalism (yes, we Russians don’t choose easy paths). According to the seller, it kills all kinds of germs, infections and viruses, including Covid-19 and Ebola. Or you can just wash your socks with it.A seller from Tyumen sells garlic charged by a village healer with the healing powers of diverting Covid-19.This Coronavirus Mop costs 500 rubles, with 200% markup from a regular one. It is an effective tool to rid the house of infection.In the Russian pharmaceutical industry, there’s a scramble to register and market old OTC and Rx drugs as the brand-new Covid-19 treatments. Some are toxic like Areprivil; others are placebo like Arbidol. There are billions of dollars to be made and the race is on!Putin promised to make 100 billion dollars from selling Sputnik V vaccine against Covid-19 which hasn’t even passed phase 3 clinical trials. He didn’t mention what he was planning to do with all that money. It’s a huge, round, off-the-wall, forecasted number. In other words, this is exactly what we, Russians, believe far more than statistics and data.

I agree with Peter Fabian's advice about a fresh set of clothes and basic toiletries, although I would put those in the rolling bag that goes in the overhead bin. I also keep a clean pair of pajamas and an second extra set of base layer apparel in the rolling bag, because if I get stuck overnight at the O'Hare Hilton or elsewhere I want to be able to take a hot shower and sleep in comfort.In the second, smaller bag at my feet I would consider bringing the following for their in-flight utility:a fully charged, good capacity USB backup battery to keep my iPhone and iPad mini going if necessary, and the power cable(s) I needone or two great magazine(s), just in casea small purse mirror (these are great for distracting a crying baby if you end up sitting next to one)a bottle of water and whatever OTC painkiller and/or allergy medicine you favor, and of course any prescription meds you might be ona clean handkerchief and/or full package of tissues (I usually carry a few tissues or a hanky in my pocket) -- each has its advantages but tissues are obviously better if you need to offer one to someone sitting near you, and you can grab some from the lavatory if you've run out or forgotten themeyeglass cleaning clothbusiness cards (you never know when you will sit next to a really interesting person)a not-too-perishable and not-easily-crushable snacka couple of bags of your favorite bagged tea or tisanelip balm and a small tube of hand cream (this I carry in my pocket or in an easily accessible external pocket of the bag)on a domestic flight within the US, in economy class, one credit card in an easily accessible pocket of the bag so that I can conveniently buy a drink or some onboard foodon an international flight, my passport and a ballpoint pen, also in an easily accessible external pocket of the bag (for those Customs and Immigration forms) (the copy of your passport can be in the rolling bag)on an international flight, a credit card in that easily accessible pocket of the bag, in case I decide to get into the Duty Free cataloga small notebook (and pen if you would not otherwise have one)sugarless gum (also in an accessible outer pocket)a pashmina, lightweight lap blanket, or other warm wrap you can use if the cabin is very cold (this saved my life once on a FRIGID flight from Paris to San Francisco)These items are all in addition to the standard in-flight comforts like music and headphones, sleeping mask, earplugs if you like them, and reading material of your choosing. Obviously each traveler should decide what is necessary for them. I tend not to use my laptop in economy class at all (there is so little space for it), so I leave it in the wheelie bag stashed overhead.

Let f(a,b,c,d,e,f) be a hypothetical function giving time equivalence at a place whose lattide and longitude should be given by another function for a place. a is second, b is minutes, c is hours, d is day, e is month,f is years of the given timeDilated time is given by Lorentz reaction,T’=T/√(1–(v²/c²))T is stationary timeV is your velocity, c is velocity of speedSo for going 1 day ahead of other the difference in time for you should be 1 minute.1 day=24×60×60 seconds,1 minute=60 seconds.24×60×60=60/√(1-(v²/c²))Which give 99.9999999% of speed of light. It means this equation take you to future.but it is 1 way.Einstein said that there exist a closed time curves. In which history is said to be repeated after a given time which implies that if we get out of that then certainly we are able to come back in time and it also doesn't want speed of light.Another way is quantum tunneling. Its actually hypothetical according to modern physics. Professor at Massachusetts institute believed that it is possible without affecting “twin paradox”.the time independent Schrödinger wave equation says that[math]{\displaystyle -{\frac {\hbar ^{2}}{2m}}{\frac {d^{2}}{dx^{2}}}\Psi (x)+V(x)\Psi (x)=E\Psi (x)}[/math]or[math]{\displaystyle {\frac {d^{2}}{dx^{2}}}\Psi (x)={\frac {2m}{\hbar ^{2}}}\left(V(x)-E\right)\Psi (x)\equiv {\frac {2m}{\hbar ^{2}}}M(x)\Psi (x),}[/math]where [math]{\displaystyle \hbar }[/math] is the reduced Planck's constant, m is the particle mass, x represents distance measured in the direction of motion of the particle, Ψ is the Schrödinger wave function, V is the potential energy of the particle (measured relative to any convenient reference level), E is the energy of the particle that is associated with motion in the x-axis (measured relative to V), and M(x) is a quantity defined by V(x) – E which has no accepted name in physics.The solutions of the Schrödinger equation take different forms for different values of x, depending on whether M(x) is positive or negative. When M(x) is constant and negative, then the Schrödinger equation can be written in the form[math]{\displaystyle {\frac {d^{2}}{dx^{2}}}\Psi (x)={\frac {2m}{\hbar ^{2}}}M(x)\Psi (x)=-k^{2}\Psi (x),\;\;\;\;\;\;\mathrm {where} \;\;\;k^{2}=-{\frac {2m}{\hbar ^{2}}}M.}[/math]The solutions of this equation represent traveling waves, with phase-constant +k or -k. Alternatively, if M(x) is constant and positive, then the Schrödinger equation can be written in the form[math]{\displaystyle {\frac {d^{2}}{dx^{2}}}\Psi (x)={\frac {2m}{\hbar ^{2}}}M(x)\Psi (x)={\kappa }^{2}\Psi (x),\;\;\;\;\;\;\mathrm {where} \;\;\;{\kappa }^{2}={\frac {2m}{\hbar ^{2}}}M.}[/math]The solutions of this equation are rising and falling exponentials in the form of evanescent waves. When M(x) varies with position, the same difference in behaviour occurs, depending on whether M(x) is negative or positive. It follows that the sign of M(x) determines the nature of the medium, with negative M(x) corresponding to medium A as described above and positive M(x) corresponding to medium B. It thus follows that evanescent wave coupling can occur if a region of positive M(x) is sandwiched between two regions of negative M(x), hence creating a potential barrier.The mathematics of dealing with the situation where M(x) varies with x is difficult, except in special cases that usually do not correspond to physical reality. A discussion of the semi-classical approximate method, as found in physics textbooks, is given . A full and complicated mathematical treatment appears in the 1965 monograph by Fröman and Fröman noted below. Their ideas have not been incorporated into physics textbooks, but their corrections have little quantitative effect.The wave function is expressed as the exponential of a function:[math]{\displaystyle \Psi (x)=e^{\Phi (x)}}[/math], where [math]{\displaystyle \Phi ''(x)+\Phi '(x)^{2}={\frac {2m}{\hbar ^{2}}}\left(V(x)-E\right).}[/math][math]{\displaystyle \Phi '(x)}[/math] is then separated into real and imaginary parts:[math]{\displaystyle \Phi '(x)=A(x)+iB(x)}[/math], where A(x) and B(x) are real-valued functions.Substituting the second equation into the first and using the fact that the imaginary part needs to be 0 results in:[math]{\displaystyle A'(x)+A(x)^{2}-B(x)^{2}={\frac {2m}{\hbar ^{2}}}\left(V(x)-E\right)}[/math].To solve this equation using the semiclassical approximation, each function must be expanded as a power series in [math]{\displaystyle \hbar }[/math]. From the equations, the power series must start with at least an order of [math]{\displaystyle \hbar ^{-1}}[/math] to satisfy the real part of the equation; for a good classical limit starting with the highest power of Planck's constant possible is preferable, which leads to[math]{\displaystyle A(x)={\frac {1}{\hbar }}\sum _{k=0}^{\infty }\hbar ^{k}A_{k}(x)}[/math]and[math]{\displaystyle B(x)={\frac {1}{\hbar }}\sum _{k=0}^{\infty }\hbar ^{k}B_{k}(x)}[/math],with the following constraints on the lowest order terms,[math]{\displaystyle A_{0}(x)^{2}-B_{0}(x)^{2}=2m\left(V(x)-E\right)}[/math]and[math]{\displaystyle A_{0}(x)B_{0}(x)=0}[/math].At this point two extreme cases can be considered.Case 1 If the amplitude varies slowly as compared to the phase [math]{\displaystyle A_{0}(x)=0}[/math] and[math]{\displaystyle B_{0}(x)=\pm {\sqrt {2m\left(E-V(x)\right)}}}[/math]which corresponds to classical motion. Resolving the next order of expansion yields[math]{\displaystyle \Psi (x)\approx C{\frac {e^{i\int dx{\sqrt {{\frac {2m}{\hbar ^{2}}}\left(E-V(x)\right)}}+\theta }}{\sqrt[{4}]{{\frac {2m}{\hbar ^{2}}}\left(E-V(x)\right)}}}}[/math]Case 2If the phase varies slowly as compared to the amplitude, [math]{\displaystyle B_{0}(x)=0}[/math] and[math]{\displaystyle A_{0}(x)=\pm {\sqrt {2m\left(V(x)-E\right)}}}[/math]which corresponds to tunnelling. Resolving the next order of the expansion yields[math]{\displaystyle \Psi (x)\approx {\frac {C_{+}e^{+\int dx{\sqrt {{\frac {2m}{\hbar ^{2}}}\left(V(x)-E\right)}}}+C_{-}e^{-\int dx{\sqrt {{\frac {2m}{\hbar ^{2}}}\left(V(x)-E\right)}}}}{\sqrt[{4}]{{\frac {2m}{\hbar ^{2}}}\left(V(x)-E\right)}}}}[/math]In both cases it is apparent from the denominator that both these approximate solutions are bad near the classical turning points [math]{\displaystyle E=V(x)}[/math]. Away from the potential hill, the particle acts similar to a free and oscillating wave; beneath the potential hill, the particle undergoes exponential changes in amplitude. By considering the behaviour at these limits and classical turning points a global solution can be made.To start, choose a classical turning point, [math]{\displaystyle x_{1}}[/math]and expand [math]{\displaystyle {\frac {2m}{\hbar ^{2}}}\left(V(x)-E\right)}[/math] in a power series about [math]{\displaystyle x_{1}}[/math]:[math]{\displaystyle {\frac {2m}{\hbar ^{2}}}\left(V(x)-E\right)=v_{1}(x-x_{1})+v_{2}(x-x_{1})^{2}+\cdots }[/math]Keeping only the first order term ensures linearity:[math]{\displaystyle {\frac {2m}{\hbar ^{2}}}\left(V(x)-E\right)=v_{1}(x-x_{1})}[/math].Using this approximation, the equation near [math]{\displaystyle x_{1}}[/math] becomes a differential equation:[math]{\displaystyle {\frac {d^{2}}{dx^{2}}}\Psi (x)=v_{1}(x-x_{1})\Psi (x)}[/math].This can be solved using Airy functions as solutions.[math]{\displaystyle \Psi (x)=C_{A}Ai\left({\sqrt[{3}]{v_{1}}}(x-x_{1})\right)+C_{B}Bi\left({\sqrt[{3}]{v_{1}}}(x-x_{1})\right)}[/math]Taking these solutions for all classical turning points, a global solution can be formed that links the limiting solutions. Given the 2 coefficients on one side of a classical turning point, the 2 coefficients on the other side of a classical turning point can be determined by using this local solution to connect them.Hence, the Airy function solutions will asymptote into sine, cosine and exponential functions in the proper limits. The relationships between [math]{\displaystyle C,\theta }[/math] and [math]{\displaystyle C_{+},C_{-}}[/math] are[math]{\displaystyle C_{+}={\frac {1}{2}}C\cos {\left(\theta -{\frac {\pi }{4}}\right)}}[/math]and[math]{\displaystyle C_{-}=-C\sin {\left(\theta -{\frac {\pi }{4}}\right)}}[/math]With the coefficients found, the global solution can be found. Therefore, thetransmission coefficient for a particle tunnelling through a single potential barrier is[math]{\displaystyle T(E)=e^{-2\int _{x_{1}}^{x_{2}}\mathrm {d} x{\sqrt {{\frac {2m}{\hbar ^{2}}}\left[V(x)-E\right]}}}}[/math],where [math]{\displaystyle x_{1},x_{2}}[/math] are the 2 classical turning points for the potential barrier.For a rectangular barrier, this expression is simplified to:[math]{\displaystyle T(E)=e^{-2{\sqrt {{\frac {2m}{\hbar ^{2}}}(V_{0}-E)}}(x_{2}-x_{1})}={\tilde {V}}_{0}^{-(x_{2}-x_{1})}}[/math]Curves in spacetime violate Heisenberg's uncertainty principlesAccording to Heisenberg's uncertainty principle, measurements of any pair of variables must have at least a minimum amount of error. The most well-known example of the pair of variables is position and momentum, but the principle applies to any two variables that have a mathematical relationship which makes them conjugate variables. The uncertainty principle is thought to be an inherent property of quantum systems due to their wave-particle duality, rather than any observational limitations. Although previous studies have found that CTC(closed time curve)models can theoretically violate the uncertainty principle, nobody knew that this could happen for the special case of an OTC(open time curve).Despite such paradoxes, CTCs in general are compatible with general relativity; however, they are not compatible with quantum mechanics. One way to make them compatible is to extend quantum mechanics in a way that resolves the paradoxical aspects of CTCs. An example of such an extension is the Deutsch model, which makes the mathematics of quantum mechanics nonlinear, allowing for CTCs. Previously, scientists have shown that this nonlinearity leads to some unusual properties, such as the possibility to build a super quantum computer that can quickly solve some complex problems called NP-complete problems, a task that would take trillions of years using today's computers.Time dilation basically refers to the idea that time passes more slowly for a moving clock than it does for a stationary clock. The force of gravity also affects the difference in elapsed time. The greater the gravity and the greater the velocity, the greater the difference in time. Black holes,like the one depicted in Interstellar, for instance,would produce a massive amount of time dilation, due to their extreme gravitational pull.At last I want to say that time travel is 100000% possible according. Just like nobody question Issac Newton theory till Albert Einstein. Same where will happen in future .Above all what you have readed are theory no practical work.