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PDF Editor FAQ

How do I calculate the mole percentage of CH30H and H2O respectively in 60% (by mass) aqueous solution of CH30H?

% CH3OH by mass = 60 %mass of CH3OH ÷ mass of solution = 60/100Let, the mass of the solution be 100 gmTherefore, mass of CH3OH = 60 gmand mass of H20 = 40 gmmoles of CH3OH = 60/32moles of H20 = 40/18% mole of CH3OH =( moles of CH3OH ÷ total moles ) X 100 = [60/32 ÷ (60/32 + 40/18)] X 100= 45.76%% mole of H20 = 100 - 45.76 = 54.24%

Why does acetic acid have a higher boiling point than ethanol?

Acetic/ethanoic acid or simply vinegar is CH3COOH (Molecular mass : 60). Ethanol is CH3CH2OH (Molecular mass : 46).Acetic acid has a higher molecular mass than ethanol, greater number of electrons, larger size of electron cloud, greater ease of distortion of electron cloud, temporary dipole is more easily induced, stronger permanent dipole - dipole interactions, stronger intermolecular forces of attraction, greater amount of heat/thermal energy needs to be supplied to break and overcome the strong bonds resulting in acetic acid having a higher boiling point.Note : Both acetic acid and ethanol are polar in nature.

What will be percentage error in kinetic energy of a body mass= 60+- 0.3 and moving with a velocity of v=25+-0.1?

%Uncertainty in mass= 0.3/60 x100 = 0.5%% uncertainty in mass = 0.1/25 = 0.4%K.E= 1/2 mv^2K.E = m+ 2VK.E= 0.5 + 2 x 0.4K.E= 0.5 + 0.8K.E= 1.3% uncertainty.

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