Chart Of Cutting Speeds; Form Grooving Fix-Profil: Fill & Download for Free

Formula for calculating spindle power in Turning operation is:-Pc (kW) - Actual Cutting Powerap (mm) -Depth of Cutf (mm/rev) - Feed per Revolutionvc (m/min) - Cutting SpeedKc (MPa) - Specific Cutting Forceη - (Machine Coefficient)From machine salient features the spindle power is available. Assume machine coefficient as 98%. From carbide tip manufacturer’s catalog take a suitable cutting speed. Take specific cutting pressure from chart. Now depth of cut and feed rate are the unknown quantities that will get while solving the above equation. after getting the value select a depth of cut and feed rate. Cut the test piece with solved parameters and monitor the load meter. If it shows 100% load then affirm the spindle power is true as the manufacturer mentioned.

It is the force acting in the cutting direction while cutting unit area in mm with a thickness of 1 mm. This is significant to calculate the spindle power while a full load cutting test. For different grade materials specific cutting pressure will be different.Formula for calculating spindle power in Turning operation is:-Pc (kW) - Actual Cutting Powerap (mm) -Depth of Cutf (mm/rev) - Feed per Revolutionvc (m/min) - Cutting SpeedKc (MPa) - Specific Cutting Forceη - (Machine Coefficient)Formula for calculating spindle power in Milling operation is:-Pc (kW) - Actual Cutting Powerap (mm) - Depth of Cutae (mm) - Cutting Widthvf (mm/min) - Table Feed per Min.Kc (MPa) - Specific Cutting Forceη - (Machine Coefficient)The specific cutting fore is either taking from a graph or a chart prepared and tabulated from practical test at different feed rates.

I am not sure if you are referring to the thickness of your hand, or the perimeter of your hand, or both, so I will assume that you are cutting a steel plate that is an average of 1/2″ (12.7 mm) thick(the thickest part of my hand is 1″(25.4 mm), and the thinnest is 1/4″(6.35mm) so this is an estimated thickness), in the outline of my closed hand. I will simulate this as a rectangle of length and width, in which the following image explains which is which.So, according to a web source[1] , the hand, on average, measures 3.1“(79 mm) wide, and 7.1“ (180.5 mm) long. This yields a perimeter of 20.4 inches(518.2 mm). Neglecting acceleration and deceleration while cutting our outline, this yields 20.4 inches per minute(.518m/min) as our desired speed, and if we assume 80% of time is spent cutting at full speed, this would yield 24.5 inches per minute(.6218 m/min). This is not astonishingly fast for a laser cutter, but since this is half inch material, the speeds are typically lower, and the laser powers required typically higher, than, say, one eighth inch material.A quick web search for cutting speeds for lasers yielded a company advertising speeds for various 4 kW lasers. Their charts include cutting speeds for oxygen cutting of mild steel for Nd:YAG disk lasers, CO2 lasers, and Fiber lasers.[2]Their chart lists CO2 Lasers as cutting .5″ material at 56 IPM(inches/minute), Nd:YAG Disk Lasers as cutting at 52 IPM, and Fiber Lasers as cutting at 60 IPM. This is more than double the speed we have calculated we will need. Lasers do not exactly double in speed with each doubling in power, but generally, it is safe to say that if you cut the power in half the speed should be around half.(Since the higher power laser is slightly slower than double the speed of a laser with half the power, our answer will be conservative)So, essentially, we can most likely complete the task of cutting a hand sized steel object in a minute with a 2 kW laser of either a Disk, Fiber, or CO2 type laser source. If the object needs to be stainless steel, aluminum or copper, or if it has a large number of holes, causing additional cutting distance, then up sizing to a 3 or 4 kW system is likely a good idea.Footnotes[1] Average Hand Size[2] Laser Comparison - Cutting Speed and Rate of Feed | JMTUSA