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PDF Editor FAQ

What is the molarity of a solution containing 50.00g of silver nitrate?

You had to provide the volume of the solution to get the molarity of the solution.Molarity = (mass/molar mass) × (1000mL/volume of solution in mL)Hope, this helps.

What is the mass in grams of 3.45x10-2 moles of silver nitrate?

At first glance:Molar mass of AgNO3: 169.8733 g/mol3.45*10^-2 mol * 169.8733 g/mol = 5.86062885 gUnless this is a trick question ?

What is the concentration of a solution of silver nitrate if 50.0 mL of the solution reacting with excess potassium chloride gives 10 g of precipitate?

The reaction involved here is: AgNO3 + KCl = AgCl + KNO3.The white precipitate formed is that of silver chloride, AgCl.Stoichiometrically, 1 mole of AgNO3 gives 1 mole of AgCl on treatment with excess KCl.Amount of AgCl formed = 10 gm = 10/143.5 = 0.07 mole. (Molar mass of AgCl = 143.5 gm)Therefore, amount of AgNO3 needed to form 0.o7 mole (10 gm)of AgCl = 0.07 mole.Now, number of moles of AgNO3 in 50 ml of the solution = 0.07So, number of moles of AgNO3 in 1 litre (1000 ml) = 1000 x 0.07/50 = 1.4.The concentration of the silver nitrate solution is 1.4 M.

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