E 600 N: Fill & Download for Free

All the other answers are good; I will just add that, although the street names are in mostly in hundreds (“mostly” because there are streets in between in some places further out, such as 920 E or 10240 S), it is still common to refer to those streets the way you suggest.e.g. 600 N will often be called “6th North,” or 9000 S will be called “90th south”. Listen to a traffic report from the area and you’ll see what I mean.

The Linearity of Chidambaram Nataraja Temple, Kanchipuram Ekambareshwar temple & Sri Kalahasthi temple.Recently one of my colleagues claimed that these 3 temples lie in a straight line. To find out, I marked their longitudes in Google maps & Guess what !Yes, they lie in the same longitude. i.e, Exactly 79deg 42 min EastSo what’s special about these 3 temples ? These are 3 out of the 5 temples that are clubbed together and called as Pancha boota Stalam ( Denoting 5 forms of Shiva - Fire, Water, Earth, Air & Space )Sri Kalahastheeswara - Vayu Lingam - AirEkambareshwarar - Prithivi Lingam - EarthThillai Nataraja - Aagaya Lingam - SpaceOne more interesting observation,Are there any other temples that lie in a same longitude ? Yes, I found two of them.Virudhagireeshwar Temple, VriddhachalamRamanathaswamy Temple, RameswaramBoth are termed as the Punniya stalam ( Where they dip themselves in a waterbody to wash away their sins )How did the architects designed the straightness of these temple gopuras that are more than 1000 years old and 500–600 Kms away ?What technology did they have to mark the longitudes ?Did they have a mapping system ?Why didn’t the temples deviate from the alignment, during any natural events like the tectonic plate shifting or the Tsunami ?What is the significance behind all this ?Nobody knows..Edit 1 -Thank you all for the amazing response. This is just an interesting observation, and an attempt to decode a pattern that existed for more than thousands of years ! This pattern may or may not hold any significance ( until we prove anything :-) ).To clarify on linearity, I’m posting the co-ordinates here :Sri Kalahastheeswara Temple - 13°44′58″N 79°41′54″EEkambareshwarar Temple - 12°50′51″N 79°42′00″EThillai Nataraja Temple - 11°23′58″N 79°41′36″EP.S - Even if it is a coincidence, it is worthy enough to notice right ?Edit 2 -Thanks again for the unexpected response ! To clarify a few more answers, here is an addition.All the three deities (Lingams)were worshiped from around 600AD, which was later enshrined in Temple structures by Chola kings ( Kulothunga Chola I, II ) during 11th & 12th century.Also I continue to see people claiming coincidence. Even, then it has to fall under third degree of coincidence.All are Shiva templesAll lie in same LongitudeAll are Panchaboota StalamI wouldn’t call it a coincidence.And here are the Missing Co-ordinates :Virudhagireeshwar Temple - 11.30°N 79.20°ERamanathaswamy Temple - 9.288106°N 79.317282°EKedarnath Temple - 30.7352° N, 79.0669° EThank you Ashutosh Chaturvedi for the edit !:)And the center point of undivided India was 21.149850°N 79.080598°E (Zero Mile); falls on the same line

Special Note:Before doing the calculations, we have to clear one important thing.When a spring having spring constant k is cut into two equal halves, the spring constant of each half becomes 2k and not k. If any one deviates from this will end up in misleading you! Please be cautious.I will prove the above result, after solving your question.Solution for you question:The Spring constant of the given spring=300 N/m (given)Therefore, the spring constant of eachhalf-spring = 2x300 N/m = 600 N/mLet the extension in each spring be = e metresTherefore, the tension in each spring= spring constant x extension= 600 N/m x e m= 600e NTherefore, (600e + 600e) N = 6 N (for equilibrium)1200e =6e =6/1200 = 1/200 = 0.5/100= 0.005 m or 0.5 cm………………………………………………………………….. Proof of spring constant for the half-spring:Spring constant for full spring=300 N/mTherefore, when 300 N is applied, the whole spring will extend by 1 m.Therefore, each half of the spring extend by 0.5 metre for the force of 300 N.Force constant for the half springo, k’ =force per unit length of extension.=force/extension =300N/0.5 m = 600 N/m